JavaScript实现信用卡校验方法
编程学习 2021-07-04 21:47www.dzhlxh.cn编程入门
这篇文章主要介绍了JavaScript实现信用卡校验方法,涉及javascript使用Luhn算法进行校验的技巧,非常具有实用价值,需要的朋友可以参考下
本文实例讲述了JavaScript实现信用卡校验方法。分享给大家供大家参考。具体分析如下:
这里JavaScript版的信用卡校验代码,采用了Luhn算法
function isValidCreditCard(type, ccnum) { if (type == "Visa") { // Visa: length 16, prefix 4, dashes optional. var re = /^4\d{3}-?\d{4}-?\d{4}-?\d{4}$/; } else if (type == "MC") { // Mastercard: length 16, prefix 51-55, dashes optional. var re = /^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/; } else if (type == "Disc") { // Discover: length 16, prefix 6011, dashes optional. var re = /^6011-?\d{4}-?\d{4}-?\d{4}$/; } else if (type == "AmEx") { // American Express: length 15, prefix 34 or 37. var re = /^3[4,7]\d{13}$/; } else if (type == "Diners") { // Diners: length 14, prefix 30, 36, or 38. var re = /^3[0,6,8]\d{12}$/; } if (!re.test(ccnum)) return false; // Remove all dashes for the checksum //checks to eliminate negative numbers ccnum = ccnum.split("-").join(""); // Checksum ("Mod 10") // Add even digits in even length strings //or odd digits in odd length strings. var checksum = 0; for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) { checksum += parseInt(ccnum.charAt(i-1)); } // Analyze odd digits in even length strings //or even digits in odd length strings. for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) { var digit = parseInt(ccnum.charAt(i-1)) * 2; if (digit < 10) { checksum += digit; } else { checksum += (digit-9); } } if ((checksum % 10) == 0) return true; else return false; }
希望本文所述对大家的javascript程序设计有所帮助。