javascript实现超炫的向上滑行菜单实例
编程学习 2021-07-04 21:48www.dzhlxh.cn编程入门
这篇文章主要介绍了javascript实现超炫的向上滑行菜单实现方法,以一个完整实例形式分析了javascript针对页面元素的遍历与样式操作相关技巧,具有一定参考借鉴价值,需要的朋友可以参考下
本文实例讲述了javascript实现超炫的向上滑行菜单。分享给大家供大家参考。具体如下：
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"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>JS实现文字上下滑动导航</title>
<style type="text/css">
body { margin:0; background:#66FF99; }
ul { padding-left:0; margin:0; }
li { list-style:none; }
#nav { height:40px; background:#900; margin-top:50px; }
#nav ul { width:240px; height:40px; margin:0 auto; }
#nav li {height:40px; width:240px;}
#nav a { float:left; width:240px;position:relative; height:40px; overflow:hidden; font-size:14px; color:#e0e03a; text-decoration:none; cursor:pointer; }
#nav strong { float:left;width:240px; }
#nav span { float:left;width:200px; padding:0 20px; height:40px; line-height:40px; background:#900; clear:both; white-space:nowrap;}
#nav .active,#nav .current span { background:#600; color:#fff; }
#nav .current .active { color:#e0e03a; }
</style>
<script>
window.onload=function()
{
var oDiv=document.getElementById('nav');
var aStrong=oDiv.getElementsByTagName('strong');
var aA=oDiv.getElementsByTagName('a');
var iTarget=oDiv.getElementsByTagName('li')[0].offsetHeight;
for(var i=0; i<aStrong.length; i++)
{
aA[i].style.width=aStrong[i].style.width=aStrong[i].getElementsByTagName('span')[0].offsetWidth+'px';
aStrong[i].style.position='absolute';
aStrong[i].style.top=aStrong[i].style.left=0;
aStrong[i].onmouseover=function()
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startMove(this, -iTarget);
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aStrong[i].onmouseout=function()
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function startMove(obj,target)
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iSpeed=iSpeed>0?Math.ceil(iSpeed):Math.floor(iSpeed);
obj.style.top=obj.offsetTop+iSpeed+'px';
}
}, 30);
}
</script>
</head>
<body>
<div id="nav">
<ul>
<li class="current">
<a href="#">
<strong>
<span>首页</span>
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希望本文所述对大家的javascript程序设计有所帮助。
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