laravel 解决paginate查询多个字段报错的问题
编程学习 2021-07-04 23:05www.dzhlxh.cn编程入门
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用laravel 框架想实现一个分页接口，返回数据表中其中一部分字段
$list = DB::table('booklist_table')->orderBy('create_time','asc')->paginate($size,['id','title','author','image'])->toJson();
return json_decode($list,true);
结果运行报错
"SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' `title`, `author`, `image`) as aggregate from `booklist_table`' at line 1 (SQL: select count(`id`, `title`, `author`, `image`) as aggregate from `booklist_table`) ◀"
后来经过查询原因将代码改为
$list = DB::table('booklist_table')->select('id','title','author','image')->orderBy('create_time','asc')->paginate($size)->toJson();
结果正确！
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