ajax实现点击不同的链接让返回的内容显示在特定
编程学习 2021-07-05 10:37www.dzhlxh.cn编程入门
过ajax实现在一个web页面点击不同的链接，然后将返回的结果显示在该页面固定的div里
/* 以下代码通过ajax实现在一个web页面点击不同的链接，然后将返回的结果显示在该页面固定的div里。 */
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
<script language="javascript">
var http_request = false;
function createRequest(url,objID){
http_request = false;
if(window.XMLHttpRequest){ //非IE浏览器
http_request = new XMLHttpRequest();
if(http_request.overrideMimeType){
http_request.overrideMimeType("text/xml");
}
}else if(window.ActiveXObject){ //IE浏览器
try{
http_request = new ActiveXObject("Msxml2.XMLHTTP");
}catch(e){
try{
http_request = new ActiveXObject("Microsoft.XMLHTTP");
}catch(e){}
}
}
if(!http_request){
alert("无法创建XMLHTTP实例");
return false;
}
http_request.open("GET",url,true);
http_request.send(null);
var obj = document.getElementById(objID);
http_request.onreadystatechange = function(){
if(http_request.readyState == 4){
if(http_request.status == 200){
obj.innerHTML = http_request.responseText;
}else{
alert('您请求的页面发现错误！');
}
}
}
}
</script>
</head>
<body onload="createRequest('content1.html','show')">
<div align="center">
<a href="content1.html" onclick="createRequest('content1.html','show');return false;">no1</a> |
<a href="content2.html" onclick="createRequest('content2.html','show');return false;">no2</a> |
<a href="content3.html" onclick="createRequest('content3.html','show');return false;">no3</a>
</div>
<div id="show" align="center"></div>
</body>
</html>